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Mademuasel [1]
3 years ago
8

A jar if dimes and quarters is worth $4.55. If there are the same number of dimes as quarters, what is the value of only the dim

es?
PLEASE HELP
Mathematics
1 answer:
Monica [59]3 years ago
8 0
For this case, the first thing we must do is define variables.
 We have then:
 x = number of dimes
 y = number of quarters
 We write the system of equations:
 0.10x + 0.25y = 4.55
 x = y
 Solving the system we have:
 x = 13
 y = 13
 The value of the dimes is:
 (0.10) * (13) = 1.3 $
 Answer:
 
The value of only the dimes is:
 
1.3 $
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Answer:

Option A

Step-by-step explanation:

Given expression:

  • 3x² - 10x - 8

<u>Option A</u>

⇒ (x - 4)(3x + 2)

⇒ (x × 3x) + (2 × x) + (-4 × 3x) + (-4 × 2)

⇒ (3x²) + (2x) + (-12x) + (-8)

⇒ 3x² + 2x - 12x - 8

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<u>Option B</u>

⇒ (3x - 4)(x - 2)

⇒ (3x × x) + (3x × -2) + (-4 × x) + (-4 × -2)

⇒ (3x²) + (-6x) + (-4x) + (8)

⇒ 3x² - 6x - 4x + (8)

⇒ 3x² - 10x + 8

3x² - 10x - 8 = 3x² - 10x + 8 (No!)

<u>Option C</u>

⇒ (3x - 4)(x + 2)

⇒ (3x × x) + (3x × 2) + (-4 × x) + (-4 × 2)

⇒ (3x²) + (6x) + (-4x) + (-8)

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3x² - 10x - 8 = 3x² + 2x - 8 (No!)

<u>Option D</u>

⇒ (3x - 2)(x - 4)

⇒ (3x × x) + (3x × -4) + (-2 × x) + (-2 × -4)

⇒ (3x²) + (-12x) + (-2x) + (8)

⇒ 3x² - 12x - 2x + 8

⇒ 3x² - 14x + 8

3x² - 10x - 8 = 3x² - 14x + 8 (No!)

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