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irakobra [83]
3 years ago
9

3^x=1÷3. Write down the value of x​

Mathematics
2 answers:
Tatiana [17]3 years ago
6 0

Answer:

x = -1

Step-by-step explanation:

3^x = 1/3

3^x= 3^-1

x=-1

True [87]3 years ago
3 0

Answer:

x=0

Step-by-step explanation:

3^x=1/3

=>3^x-1/3=0

=>(9^x-1)/3=0

=>9 ^x -1=0

=>9^x=1

=>x=0 (n^0=1)

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R+r+2r-r+4r combine like terms and solve
goldenfox [79]

R+r+2r-r+4r

R + r + 2R + 4r = R+7r

R+7r - -r =

R+6r

6 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
Magdalena Figueroa's covered medical care bills for a recent illness were $8,440.00. Her major medical policy had a coinsurance
devlian [24]
Medical bill = $8,440
Deductible = $400
Coinsurance plan = Medical policy 80% of all expenses above $400

Amount to pay = 400+ (8440-400)*20/100 = 400+1608 = $2,008
8 0
3 years ago
What is this answer?? : [6.6 ÷ (–5 + 3)] • (–1)
Mars2501 [29]
Your answer is 3.3

-Hope I helped you. :)
3 0
3 years ago
Can i please have some help??
Sliva [168]

Answer:

No solution

Step-by-step explanation:

When lines are parallel, they do not intersect and they do not have a solution.

Thank You

Hope it helps u

3 0
3 years ago
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