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Keith_Richards [23]

3 years ago

11

Polygon LMNP slides 5 units right and 4 units down on the coordinate plane. If the original measure of angle M was 50 degrees, w

hat is the measure of angle M'?

2 answers:

Mrrafil [7]3 years ago

4 0

Answer:

c

Step-by-step explanation:

sergeinik [125]3 years ago

3 0

Add them all together

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3 years ago

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kolezko [41]

Answer:

x = 19

Step-by-step explanation:

3x - 3 = 6(x - 10)

3x - 3 = 6x - 60 Use dist property

Subtract 3x from both sides

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Add 60 to both sides

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3 years ago

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Option 4:

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4 years ago

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Determine and prove what shape is formed for the given coordinates for ABCD, and then find the

ella [17]

Answer:

Square

Step-by-step explanation:

Plot points A (10,-4), B (6,-7), C (3,-3), D (7,0) on the coordinate plane.

Find slopes of the sides:

$AB:\ \dfrac{-7-(-4)}{6-10}=\dfrac{3}{4}\\ \\BC:\ \dfrac{-3-(-7)}{3-6}=-\dfrac{4}{3}\\ \\CD:\ \dfrac{0-(-3)}{7-3}=\dfrac{3}{4}\\ \\DA:\ \dfrac{-4-0}{10-7}=-\dfrac{4}{3}$

The slopes of opposite sides are the same, so opposite sides are parallel. The slopes of adjacent sides have product of -1, then adjacent sides are perpendicular.

Find the lengths of all sides:

$AB=\sqrt{(10-6)^2+(-4-(-7))^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\BC=\sqrt{(6-3)^2+(-7-(-3))^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\CD=\sqrt{(3-7)^2+(-3-0)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\AD=\sqrt{(10-7)^2+(-4-0)^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\$

All four sides are of the same length.

Quadrilateral ABCD is a square (all sides of equal length and perpendicular)

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3 years ago

What is (2x^2+2x-6) times (x-4)?

andreev551 [17]

Answer:

2x^3-6x^2-14x+24

Step-by-step explanation:

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3 years ago