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nikitadnepr [17]
3 years ago
11

Can someone answer this question for me​

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

C

Step-by-step explanation:

F is -4,-2 1 and below goes smaller if I remember correctly and Anything above goes bigger, sorry if it’s wrong and if the explanation doesn’t make sense but pretty sure it’s C

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If
Svetllana [295]
2x8x40=$160 which is the labour cost
revenue=$2000
therefore the labor cost as a percentage of Revenue is ($160/$2000) x 100
which equals 8%
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3 years ago
El lado de un cuadrado de su area es de 432m2
kari74 [83]

Answer:

Todos los lados de un cuadrado son iguales. Hay 4 lados en un cuadrado. Entonces, para encontrar un lado, debemos dividir el área por 4.

432/4 = 108, Un lado del cuadrado mide 108 metros.

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3 years ago
A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are
Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764

There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

(b) What is the probability that all three of the bulbs have the same rating?

P = P_{1} + P_{2} + P_{3}

P_{1} is the probability that all three of them are 13-watt. So:

P_{1} = \frac{8}{24}*\frac{7}{23}*\frac{6}{22} = 0.0277

P_{2} is the probability that all three of them are 18-watt. So:

P_{2} = \frac{9}{24}*\frac{8}{23}*\frac{7}{22} = 0.0415

P_{3} is the probability that all three of them are 23-watt. So:

P_{3} = \frac{7}{24}*\frac{6}{23}*\frac{5}{22} = 0.0173

P = P_{1} + P_{2} + P_{3} = 0.0277 + 0.0415 + 0.0173 = 0.0865

There is a 8.65% probability that all three of the bulbs have the same rating.

(c) What is the probability that one bulb of each type is selected?

We have to permutate, permutation of 3(bulbs), with (1,1,1) repetitions(one for each type). So

P = p^{3}_{1,1,1}*\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 3**\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 0.1245

There is a 12.45% probability that one bulb of each type is selected.

3 0
3 years ago
This is a picture of a cube and the net for this cube. plz help asap
Yakvenalex [24]
I think A not so sure
8 0
3 years ago
Read 2 more answers
Determine if the quadrilateral is a parallelogram. Using a complete sentence, explain why or why not.
Alex777 [14]

Answer:

It is

Step-by-step explanation:

Parralel Lines. Since they have the same opposite angles, they will never touch, being parallel

6 0
3 years ago
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