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Leni [432]
3 years ago
15

Find value of the variable

Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

x=10

Step-by-step explanation:

16/24=(x-2)/12

or, 16/2=x-2

or, 8=x-2

or, x-2=8

or, x=10

Answered by GAUTHMATH

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Work out 77 % of 775.66 m Give your answer rounded to 2 DP.
Zinaida [17]

Answer:

597.25 m

Step-by-step explanation:

We need to find 77% of 775.66 m.

It can be calculated as follows :

77\%\times 775.66\\\\=\dfrac{77}{100}\times 775.66\\\\=597.25\ m

So, 77% of 775.66 m is equal to 597.25 m.

6 0
3 years ago
Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb
jonny [76]

Answer:  The answer is 400  blue marbles.


Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,

and number of blue marbles is

n_b=560-364=196.

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.

Thus, 400 blue marbles need to be added to the bag.


5 0
3 years ago
Read 2 more answers
Nth term of 4,11,18,25
romanna [79]
18 is the answer because eighteenth has nth in the ending
8 0
3 years ago
Read 2 more answers
What is the value of x in the equation (2x + 1)1/3 + 3 = 6
OleMash [197]

Answer:

x = 4

Step-by-step explanation:

8 0
3 years ago
Find the area under the curve y = 27/x3 from x = 1 to x = t. Evaluate the area under this curve for t = 10, t = 100, and t = 100
Darina [25.2K]

Answer:

Step-by-step explanation:

given is a function as

y=\frac{27}{x^3}

We are to find the area form x=1 to x=t

The curve from x=1 lies in the I quadratnt.

So area  above x axis is to be calculated

Area = \int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )

a) When t =10,

area = \frac{27}{2} (1-\frac{1}{10^2} )\\= 13.365

b) t=100

area = \frac{27}{2} (1-\frac{1}{100^2} )\\= 13.49865

c) t=10000

area = \frac{27}{2} (1-\frac{1}{10000^2} )\\= 13.5

6 0
3 years ago
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