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3 years ago

13

WORTH EXTRA POINTS! Plz help me this is about using pythagorean therom to find isosolize triangels side lenghths. It really easy

7th grade math. Please help :) Thanks I will mark brainliest asap.

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

M

Step-by-step explanation:

avanturin [10]3 years ago

4 0

Answer:

<h2>Pythagorean Theorem: a^2 + b^2 = c^2</h2>

But what is the actual question?

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Solve the following system by the comparison method.

agasfer [191]

Answer:

2p + q = 1

9p + 3q + 3 = 0

q = 1 - 2p

replace q = 1 - 2p into 9p + 3q + 3 = 0

9p + 3(1 - 2p) + 3 = 0

9p + 3 - 6p + 3 = 0

3p + 6 =0

3p = -6

p = -2

q = 1 - 2p

q = 1 -2(-2)

q = 1 + 4

q = 5

(-2 , 5)

there for the answer would be

{(-2, 5)}

Hopefully this was helpful <3 :3

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3 years ago

How many counting numbers less than 500 are square numbers?

PtichkaEL [24]

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4 years ago

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riel wants to use squares to tile a floor that measures 240 cm by 300 cm what is the length of the largest square he can use

Alexxx [7]

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3 years ago

How would you use proportional relationships in real life situations? <br> Provide an example.

Shkiper50 [21]

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3 years ago

Someone answer. Will give brainlest

Leto [7]

Area inside the semi-circle and outside the triangle is (91.125π - 120) in²

Solution:

Base of the triangle = 10 in

Height of the triangle = 24 in

Area of the triangle = $\frac{1}{2} bh$

$$=\frac{1}{2} \times 10\times24$

Area of the triangle = 120 in²

Using Pythagoras theorem,

$\text{Hypotenuse}^2=\text{base}^2+\text{height}^2$

$\text{Hypotenuse}^2=10^2+24^2$

$\text{Hypotenuse}^2=100+576$

$\text{Hypotenuse}^2=676$

Taking square root on both sides, we get

Hypotenuse = 23 inch = diameter

Radius = 23 ÷ 2 = 11.5 in

Area of the semi-circle = $\frac{1}{2}\pi r^2$

$$=\frac{1}{2} \pi \times (13.5)^2$

Area of the semi-circle = 91.125π in²

Area of the shaded portion = (91.125π - 120) in²

Area inside the semi-circle and outside the triangle is (91.125π - 120) in².

5 0

3 years ago