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UkoKoshka [18]
3 years ago
11

The perimeter of a rectangle Is 108 centimeters. If the length of the rectangle is five times the width, what are the dimensions

of the rectangle?
Mathematics
1 answer:
vampirchik [111]3 years ago
4 0

Answer: L=45, W=9

Step-by-step explanation:

Perimeter P=108  so if  L=5W,

P=2(L+W)=2(5W+W)=2(6W)=12W

108=12W

W=108/12=9

L=5*9=45

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The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.
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<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

34 = 2(L + 6.5)

Thus the equation is found

<em><u>Solve for "L"</u></em>

L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5

Thus length of rectangle is 10.5 units

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The length of a rectangle is six times its width.
Hoochie [10]

Answer:

Length = 30

Width = 5

Step-by-step explanation:

So the formula for perimeter is

P = 2L+2W

And we know that:

L = 6W

So then we put in all the information that we do know

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