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UkoKoshka [18]
3 years ago
11

The perimeter of a rectangle Is 108 centimeters. If the length of the rectangle is five times the width, what are the dimensions

of the rectangle?
Mathematics
1 answer:
vampirchik [111]3 years ago
4 0

Answer: L=45, W=9

Step-by-step explanation:

Perimeter P=108  so if  L=5W,

P=2(L+W)=2(5W+W)=2(6W)=12W

108=12W

W=108/12=9

L=5*9=45

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Read 2 more answers
Enter an equation in point-slope form for the line. (6,8) and (7,1) is on the line. The equation of the line in point slope form
Yuri [45]

Answer:

y - 8 = -7(x - 6) or y - 1 = -7(x - 7)

Step-by-step explanation:

The point-slope form equation is y - b = m(x - a), where,

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m = slope = \frac{y_2 - y_1}{x_2 - x_1}

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m = \frac{1 - 8}{7 - 6}

m = \frac{-7}{1}

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There are two possible point-slope equation we can come up with using each points on the line given.

Using the point (6, 8) and m = -7,

Substitute m = -7, a = 6, and b = 8 into y - b = m(x - a)

y - 8 = -7(x - 6)

Using the point (7, 1) and m = -7,

Substitute m = -7, a = 7, and b = 1 into y - b = m(x - a)

y - 1 = -7(x - 7)

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