1) slope is 6 and y-intercept is ( 0,5) y = mx + b, m = 6, b = 5 y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 ) First find the slope: m = (3-6)/(6-3) = -3/3 = -1 y = -x + b Plug in one of the given points (x,y) and find b 6 = -3 + b 9 = b <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c where c is a constant number. y = 7 y=-3x+3x intercept: set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept: set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept: Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y
Answer:
9/10
Step-by-step explanation:
There are 20 and 2 green 20-2 is 18 so 18/20 simplified is also 9/10
Actually Welcome to the Concept of the Functions.
Let's first find the g(-1),
so we get as
3(-1)^2 +5(-1)-6
=> 3 -5-6
=> -8
now since g(-1) =-8
let's find f(g(-1)) that is f(-8)
f(-8) = 4(-8) + 14
=> f(g(-1)) = -32+14
=> f(g(-1)) = -18
-18 is the answer.
Answer:
The class average is 83.6
Step-by-step explanation:
:D
I’m not 100% sure but i think:
u can multiply 3 on both sides
3x+12=6
subtract 12 from both sides
3x=-6
therefore
x=-2
hope that helps
