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3 years ago

10 points || answer ASAP if you can

Mathematics

1 answer:

dmitriy555 [2]3 years ago

8 0

Answer:

It would affect the mean, range, and standard deviation

Step-by-step explanation:

I got this right on the test :)

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Tanya is training a turtle for a turtle race. For every 1/3 of an hour that the turtle is crawling, he can travel 2/23 of a mile

Oxana [17]

The unit rate with the turtle crawling is 6/23 mile per hour.

According to the statement

we have given that the every 1/3 of an hour that the turtle is crawling, he can travel 2/23 of a mile. and

we have to find the unit rate with the turtle crawling

So, For this purpose,

we know that the

The unit rate of speed in miles per hour the number of miles in one hour.

So, to find the unit rate:

Divide distance in miles with the time which is in hours.

So,

unit rate of speed = distance / time

unit rate of speed = (2/23) / (1/3)

unit rate of speed = 6/23 mile per hour.

So, The unit rate with the turtle crawling is 6/23 mile per hour.

Learn more about unit rate here

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8 0

1 year ago

A local pizza shop has a membership program for frequent buyers. The membership costs $10 per month and members get a discounted

dmitriy555 [2]

Answer:

Monthly cost = $10 + $1.75x

Step-by-step explanation:

Given the following :

Membership cost = $10 per month

Discounted price for members = $1.75 per slice of pizza

If Autum purchased the membership, the monthly cost for x slices of pizza

Monthly cost of x slices will be :

Membership cost + (discounted price * number of slices)

Monthly cost = $10 + ($1.75 * x)

Monthly cost = $10 + $1.75x

8 0

3 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago

The output with the y being -4

aivan3 [116]

For this case we have a function of the form $y = f (x)$ , where $f (x) = - 4x$ . We must find the values of "and" according to the following function: $y = -4x$