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azamat
3 years ago
14

Multiply (x^3 + 3x^2 + 3)(3x^3 − 6x^2 − 8x + 1)

Mathematics
2 answers:
ElenaW [278]3 years ago
4 0
When multiplying two equations like this, you need to distribute. Distribute each term to get <span><span><span><span><span><span>3<span>x</span></span></span></span></span></span></span>x^{6} <span><span><span><span><span>+ <span>3</span></span></span></span></span></span>x^{5}<span><span><span><span>− <span>26</span></span></span></span></span>x^{4}<span><span><span>−<span>14</span></span></span></span>x^{3}<span><span>−<span>15</span></span></span>x^{2}<span>−<span>24x</span></span>+<span>3</span>
Allisa [31]3 years ago
3 0
The answer is 3x^6 + 3x^5 - 26x^4 - 14x^3 - 15x^2 - 24x + 3.
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9. Solve the following system of equations. x + 2y − 6 = z 3y − 2z = 7 4 + 3x = 2y − 5z A. x = 0, y = 5, z = 4 B. C. D. x = 2, y
Inessa [10]
X + 2y - 6 = z..........x + 2y - z = 6
3y - 2z = 7
4 + 3x = 2y - 5z.....3x - 2y + 5z = -4

x + 2y - z = 6.....multiply by -3
3x - 2y + 5z = -4
---------------------
-3x - 6y + 3z = -18 (result of multiplying by -3)
3x - 2y + 5z = -4
--------------------add
-8y + 8z = - 22

-8y + 8z = -22
3y - 2z = 7 .....multiply by 4
----------------
-8y + 8z = -22
12y - 8z = 28 (result of multiplying by 4)
----------------add
4y = 6
y = 6/4 reduces to 3/2

-8y + 8z = -22
-8(3/2) + 8z = -22
-12 + 8z = -22
8z = -22 + 12
8z = -10
z = -10/8 reduces to -5/4

x + 2y - 6 = z
x + 2(3/2) - 6 = -5/4
x + 3 - 6 = -5/4
x - 3 = -5/4
x = -5/4 + 3
x = -5/4 + 12/4
x = 7/4

solution is (7/4, 3/2, -5/4).....x = 7/4, y = 3/2, and z = -5/4
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