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Andreas93 [3]
3 years ago
13

No more chocolate or transporters​

Mathematics
2 answers:
shusha [124]3 years ago
6 0

Answer:

huh?

Step-by-step explanation:

did you forget a pic?

Goryan [66]3 years ago
5 0

Answer:

thats absolutely right

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John owes a debt of $500 to his landlord. His father has agreed to pay 3/5
Furkat [3]
John’s father will pay $300.

If you divide $500 into 5 equal parts, each part will be comprised of $100. In other words, 1/5 of $500 is $100. This is proven because $100 • 5 = $500.

But since you are trying to find 3/5 of $500, (not 1/5, which is what we just found). This means we must find the total value of 3 of the five equal parts. To do this, multiply
$100 • 3, since $100 is 1/5 of $500.
$100 • 3=$300, so the answer is B. Johns father will pay $300.
8 0
3 years ago
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You have a frame that holds three pictures. You pulled out your favorite five photos. How many sets of three are there? Make a l
soldi70 [24.7K]

Answer:

10

Step-by-step explanation:

nCr = 5!/(3! × (5 - 3)!)

= 10

123/ 124/ 125/ 134/ 135/ 145/ 234/ 235/ 245/ 345

The formula for combinations is generally n! / (r! (n -- r)!), where n is the total number of possibilities to start and r is the number of selections made. In our example, we have 52 cards; therefore, n = 52.

6 0
4 years ago
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Which complex number has a distance of 17 from the origin on the complex plane?
Virty [35]

Answer:

None of the options are correct.

Step-by-step explanation:

Let the complex number is a + ib

Given distance from origin = 17 units

Now, by distance formula distance of a point  from the origin  =

17 = \sqrt{(x)^{2}  + (y)^{2} }

1) <u>Check for 2 + 15 i</u>

here, \sqrt{15^2  +  2^2}  = \sqrt{225 + 4} = \sqrt{229} ≠ 17

2)<u> Check for 17 +  i</u>

here, \sqrt{17^2  +  1^2}  = \sqrt{289 + 1} = \sqrt{290}≠ 17

3)<u> Check for 20 - 3 i</u>

here, \sqrt{20^2  +  (-3)^2}  = \sqrt{400 + 9} = \sqrt{409}≠ 17

4) <u>Check for 4 -  i</u>

here, \sqrt{4^2  +  (-1)^2}  = \sqrt{16 + 1} = \sqrt{17} ≠ 17

Hence,  none of the options are correct.

4 0
4 years ago
What is the solution to the compound inequality? –6 ≤ 2x + 6 ≤ 6
maw [93]

∈  ≤ ≥

-6 ≤ 2x + 6 ≤ 6 ( seperate the two inequalities)

2x + 6 ≥ - 6

2x + 6 ≤ 6 (solve the inequalities)

x ≥ -6

x ≤ 0 (find the intersection)

solution is : x ∈  { -6, 0 }

7 0
4 years ago
Solve the equation and check answers x=24=32/4
Firlakuza [10]
Your equation has no solution.

Hope this helped! c:


7 0
3 years ago
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