The fish population in a local lake is 10,000. The population increase by half every year. Which function represents the fish po pulation after x years? 1. f(x) = 1.5(10,000)^x
2. 10,000(-1.5)^x
3. None
4. f(x) = 10,000(0.5)^x
5. f(x) = 10,000 (1.5)^x
2 answers:
Answer:
5. f(x) = 10,000 (1.5)^x
Step-by-step explanation:
We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.
Let's test it.
Initial:
10,000
After 1 year
10,000 + (.5*10000)
10,000 + 5000 = 15,000
After 2 years
15,000 + (.5*15000)
15,000 + 7500 = 22,500
Let's try our equation.
f(x) = 10,000 (1.5)^x
x = 2
10,000(1.5)^2
10,000(2.25) = 22,500
The same!
The answer is 4. Explanation: Every year the population increases by half of the current population, so it goes up 5,000 every year
You might be interested in
Step-by-step explanation:
apples:17%
pears:25%
peaches:13%
oranges:46%
Answer:
B. H(w) gets very small.
Step-by-step explanation:
This should be the answer you're looking for