All categories

3 years ago

PLEASE HELP ME IN GEOMETRY!!!

Mathematics

1 answer:

puteri [66]3 years ago

7 0

Answer:

7.20

Step-by-step explanation:

triangle is right triangle so other leg of first is 12

5 x 3/5 = 5, so

do 12 x 3/5 to get 7.20

You might be interested in

Find the mean 3,4,4,2,5,7,2

stich3 [128]

Thats 3.85714285714 because if you add the numbers and divide by the numbers they are it’ll be 3.85714285714

7 0

2 years ago

The lengths of two sides of a triangle are 4 cm 4 cm and 20 cm . 20 cm. Identify the correct pair of measures between which the

Gennadij [26K]

Answer:

I think what you meant to say is "If a triangle has 2 sides that are 4 cm and 20 cm, what are the possible lengths of the third side?"

Basically, when given 2 sides of a triangle, the third side must be GREATER than the DIFFERENCE of the other 2 sides and LESS than the SUM of the other 2 sides.

difference = 16 cm

sum = 24 cm

So, the third side must be greater than 16 cm and less than 24 cm

Step-by-step explanation:

4 0

3 years ago

How do I solve problems like this? <br><br> X + 1/2 = 4/6

andrezito [222]

Answer:

1/3

Step-by-step explanation:

pic bleow

also can u help or someone

draw three cells in parallel, two light bulbs (loads) in series, with one switch.

5 0

2 years ago

a ferry boat collects 67 people at pier one. At pier two 36 people get on and 23 people get off. At pier three 18 get on and 29

GREYUIT [131]

Starts off with 67 people.

Pier two: 67 + 36

103 - 23 = 80

Pier three: 80 + 18

98 - 29 = 69

There will be 69 people on the boat heading for Pier four

6 0

3 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

eimsori [14]

Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term $2x^2$ , which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

2) if its vertex is below the x-axis, the parabola's branches are forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression:

$x_v=\frac{-b}{2a}$

Since in our case $a=2$ and $b=-3$ , we get that the x-position of the vertex is:

$x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

$y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}$

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

$f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6$

See the graph produced in the attached image.

4 0

3 years ago