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KengaRu [80]
3 years ago
8

How do you find the derivative of h(t)=sqrt(t)(1-t^2)

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

Step-by-step explanation:

h(t)=\sqrt{(t)(1-t^2)}\\h^{2}(t)=t(1-t^2)=t-t^3\\ diff. w.r.t.,\\2 h(t)h'(t)=1-3t^2\\h'(t)=\frac{1-3t^2}{2 h(t)} \\h'(t)=\frac{1-3t^2}{2\sqrt{(t)(1-t^2)} }

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