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daser333 [38]
4 years ago
12

How do i do this. Im mad lost

Mathematics
1 answer:
ZanzabumX [31]4 years ago
3 0

Answer:

x-int: (8/3, 0)

y-int: (0, -32/3)

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

x-intercept is the x-value when y = 0

y-intercept is the y-value when x = 0

Step 1: Write equation

2x - 1/3 = 1/2y + 5

Step 2: Subtract 5 on both sides

2x - 16/3 = 1/2y

Step 3: Multiply 2 on both sides

4x - 32/3 = y

Step 4: Rewrite

y = 4x - 32/3

Step 5: Find x-int

0 = 4x - 32/3

32/3 = 4x

x = 8/3

(8/3, 0)

Step 6: Find y-int

y = 4(0) - 32/3

y = 0 - 32/3

y = -32/3

(0, -32/3)

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The ratio of tagged fish to untagged fish was 2 to 9. Ninety fish were tagged. How many fish were untagged
Nimfa-mama [501]

Answer:

405

Step-by-step explanation:

Since

2 : 9 = 90 : X

Then we know

9/2 = X/90

Multiplying both sides by 90 cancels on the right

90 × (9/2) = (X/90) × 90

90 × (9/2) = X

Then solving for X

X = 90 × (9/2)

X = 405

Therefore

2 : 9 = 90 : 405

5 0
3 years ago
Write an equation of a line through the point (-5, -2) that is perpendicular to the x-axis. State the slope of the line.
zmey [24]
Perpendicular to x axis means then that the euation is x=something
given
(-5,-2)
(x,y)
so x=-5 is da equation
8 0
3 years ago
Write a linear equation in standard form for the line that goes through (4,3)<br> and (8,2).
notsponge [240]

Answer:

Ax + By = C

A, B and C can be any number--including negative numbers, zero and one! So examples of standard form can look like this:

3_x_ + 7_y_ = 10, where A = 3, B = 7 and C = 10.

Or they can look like this:

x + 5_y_ = 6. In this case, A = 1, B = 5 and C = 6.

Or this:

8_y_ = 9. In this case, A = 0, which is why x does not appear in the equation. B = 8 and C = 9, as you would expect.

And here's one more:

3_x_ − 5_y_ = 12. Here, A = 3, B = −5 and C = 12. Notice that in this case, B is negative five!

The standard form of a linear equation is Ax + By = C, where A, B and C can be any number.

3 0
4 years ago
Trigonometry please please please please help
ANEK [815]

Answer:

104

Step-by-step explanation:

you have to add both numbers up

6 0
3 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
mixer [17]

Answer:

Step-by-step explanation:

First I want to set up some variables.

S = sum

n = final term

ax = xth term, so a1 is the first term and an is the last one

d = common difference.

There are two formulas to find the sum, if you don't get how they were gotten I'd be happy to explain.

S = (n/2)(a1+an) = (n/2)(2a1+(n-1)d)

So, to find n we use the first one.

S = (n/2)(a1+an)

123 = (n/2)(8+33)

123 = (n/2)41

3 = n/2

6 = n

Now we can find d with the other one

S = (n/2)(2a1+(n-1)d)

123 = (6/2)(2*8+(6-1)d)

123 = 3(16+5d)

41 = 16+5d

25 = 5d

5 = d

so there are six terms and the common  difference is 5.

8 0
4 years ago
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