Answer:
405
Step-by-step explanation:
Since
2 : 9 = 90 : X
Then we know
9/2 = X/90
Multiplying both sides by 90 cancels on the right
90 × (9/2) = (X/90) × 90
90 × (9/2) = X
Then solving for X
X = 90 × (9/2)
X = 405
Therefore
2 : 9 = 90 : 405
Perpendicular to x axis means then that the euation is x=something
given
(-5,-2)
(x,y)
so x=-5 is da equation
Answer:
Ax + By = C
A, B and C can be any number--including negative numbers, zero and one! So examples of standard form can look like this:
3_x_ + 7_y_ = 10, where A = 3, B = 7 and C = 10.
Or they can look like this:
x + 5_y_ = 6. In this case, A = 1, B = 5 and C = 6.
Or this:
8_y_ = 9. In this case, A = 0, which is why x does not appear in the equation. B = 8 and C = 9, as you would expect.
And here's one more:
3_x_ − 5_y_ = 12. Here, A = 3, B = −5 and C = 12. Notice that in this case, B is negative five!
The standard form of a linear equation is Ax + By = C, where A, B and C can be any number.
Answer:
104
Step-by-step explanation:
you have to add both numbers up
Answer:
Step-by-step explanation:
First I want to set up some variables.
S = sum
n = final term
ax = xth term, so a1 is the first term and an is the last one
d = common difference.
There are two formulas to find the sum, if you don't get how they were gotten I'd be happy to explain.
S = (n/2)(a1+an) = (n/2)(2a1+(n-1)d)
So, to find n we use the first one.
S = (n/2)(a1+an)
123 = (n/2)(8+33)
123 = (n/2)41
3 = n/2
6 = n
Now we can find d with the other one
S = (n/2)(2a1+(n-1)d)
123 = (6/2)(2*8+(6-1)d)
123 = 3(16+5d)
41 = 16+5d
25 = 5d
5 = d
so there are six terms and the common difference is 5.