Question

Determine the 57th term of the sequence 672,660,648...

Answer 1

It appears the sequence is arithmetic because it has a common difference, d, of -12.
$d= a_{2} -a_{1}=a_{3}-a_{2}=a_{4}-a_{3}= ...=a_{n}-a_{n-1}$
Formula for any term in an arithmetic sequence is $a_{n}=a_{1}+d(n-1)$
n = 57, $a_{1}=672$, d = -12

Substitute values into formula:
$a_{57}=672-12(57-1)$
$a_{57}=0$

Answer 2

The 57th term of the sequence is 0.

Hope this helps! :)

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