The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
<h3>How to determine the coordinates of the vertex that A maps to after the two reflections?</h3>
From the given figure, the coordinate of the vertex A is represented as:
A = (-5, 2)
<u>The coordinates of the vertex that A maps to after Daniel's reflections</u>
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A' = (5 - 2, 2)
Evaluate the difference
A' = (3, 2)
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A'' = (3, -2 + 4)
Evaluate the difference
A'' = (3, 4)
Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)
<u>The coordinates of the vertex that A maps to after Zachary's reflections</u>
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A' = (-5, -2 + 4)
Evaluate the difference
A' = (-5, 2)
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A'' = (5 - 2, 2)
Evaluate the difference
A'' = (3, 2)
Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
Read more about reflection at:
brainly.com/question/4289712
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Answer:
Step-by-step explanation:
These cannot combine the way they are. The rule for adding and subtracting radicals is really picky. Not only does the index have to be the same (the little number that is sitting outside in the bend of the radical {ours is a 2, which isn't usually there, but is instead understood to be a square root}), but the radicand, the expression under the square root (or cubed root, or fourth root, etc) has to the same as well. All of our radicals are square roots, so that's good, but the radicands are all different. The first one is an 8, the next one is a 72, and the last one is a 50. BUT if we can rewrite them by simplifying them and then the radicands are the same, we're in good shape.
Simplify by taking the prime factorization of each of those numbers.
8: 4*2 and 4 is a perfect square, so we'll stop there
72: 36*2 and 36 is a perfect square, so we'll stop there
50: 25*2 and 25 is a perfect square, so we'll stop there.
Now, rewrite each one of them in terms of their prime factorization:
and then pull out each perfect square as its root:
and now all the radicands are the same, so we can add them to get
or simply 
Answer:
1/6
Step-by-step explanation:
If we're assuming that this is a six-sided die, then we can find that the results can be 1,2,3,4,5,6. Only 1 of those 6 numbers are 5, so the probability of the cube landing on 5 would be 1/6.
