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sasho [114]
3 years ago
13

Which ratio is equivalent to 10 : 85 20/170 2/15 5/42 20/95

Mathematics
1 answer:
QveST [7]3 years ago
7 0
The simplest form of
10 \div 85
is

2/17



now if we see the first option i.e

20/170 we see on simplifying that


it's same as


2/17





hence option 20/170 is correct
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Parallelogram PQRS is shown on the coordinate grid. Parallelogram PQRS is dilated with the origin as the center of dilation usin
Gwar [14]

Answer:

B) Parallelogram P'Q'R'S' is smaller than parallelogram PQRS, because the scale factor is less than 1.  

Step-by-step explanation:

Given that Parallelogram PQRS is shown on the coordinate grid. Parallelogram PQRS is dilated with the origin as the center of dilation using the rule (x, y) → (0.75x, 0.75y) to create parallelogram P'Q'R'S'.

This means that sides of PQRS would be 0.75 times the sides of the original PQRS

Or PQRS will be larger

B) Parallelogram P'Q'R'S' is smaller than parallelogram PQRS, because the scale factor is less than 1.  

is the right answer

7 0
3 years ago
Marc mows lawns for $25 each lawn, plus $5 for every hour he spends mowing. The equation for his total earnings per lawn is y =
Mila [183]

Answer:

<h2>The flat pay $25 represents the intercept</h2>

Step-by-step explanation:

To answer this question we need to first understand and compare it with the equation of straight line.

i.e y= mx+c  which is the equation of line

where m= slope

           y= dependent variable

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          c= intercept

Given

y= 25+5h

comparing both expression we can see that

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6 0
3 years ago
Thorium -228 is a radioactive substance that decays 50% every 1.9 years. How much of a 50 gram sample will exist after 22.8 year
Evgesh-ka [11]

Answer:

A=0.0122\ gr

Step-by-step explanation:

The exponential decrease formula that we must use is:

A=A_0e^ {-kt}

Where A is the amount of thorium as a function of time

A_0 is the initial amount and k is the decrease rate

We know that initially there are 50 gr and that you decay 50% every 1.9 years.

So

A=A_0*0.5=50*0.5 = 25\\\\t=1.9

25=50e^ {-k(1.9)}

We solve the equation for k

0.5=e^ {-k(1.9)}

ln(0.5)=ln(e^ {-k(1.9)})

ln(0.5)=-k(1.9)

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k=-\frac{ln(0.5)}{1.9}\\\\k=0.3648

After 22.8 years the amount of thorium that exists is:

A=50e^ {-0.3648(22.8)}

A=0.0122\ gr

5 0
4 years ago
1.Jon travels 1/2 mile in 1/4 hour. Find the unit rate in miles per hour.
Evgen [1.6K]
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5 0
3 years ago
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oksano4ka [1.4K]

Answer:

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4 0
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