Answer:
<u>Given</u>
- tanθ = 3.454
- θ is in the III quadrant
We know in the III quadrant both sine and cosine are negative.
<u>Use the following identities to get values of sinθ and cos θ</u>
- sinθ = - tanθ/√(1 +tan²θ)
- cosθ = - 1/√(1 +tan²θ)
<u>Substitute the value of tanθ and find sine and cosine:</u>
- sinθ = - 3.454/√(1 + 3.454²) = - 0.961
- cosθ = - 1/√(1 + 3.454²) = - 0.278
One cup of flour will be e left
B, 1.2, is greater in value than 115%
Answer:
2qp+r
Step-by-step explanation:
Double q (2q)
Multiply that by p (2qp)
Add that to r (2qp+r)
-20a-28 I believe is the answer!
You first distribute 7 into -2a-4, which gets -6a-14a-28. You then combine like terms -6a and -14a, to get -20a-28 which you cannot combine anymore!
Hopefully that’s correct :3