There are three elements in that set.
Answer:
w=-11/6
Step-by-step explanation:
Step-by-step explanation:
factor 4 out of the variable terms, as this helps.
but my approach is simply to define the target and then calculate "backwards".
we want to find
(ax + b)² = a²x² + 2abx + b²
and now we compare with the original equation :
a²x² = 4x²
a² = 4
a = 2
2abx = 16x
2×2×bx = 16x
4b = 16
b = 4
b² = 16, but we have only 3, so we need to subtract 16-3 = 13 from the completed square.
so, our equation is
(2x + 4)² - 13 = 0
(2x + 4)² = 13
2x + 4 = sqrt(13)
2x = sqrt(13) - 4
x = sqrt(13)/2 - 2
Answer:
Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.
Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity
Step-by-step explanation:
Given that the vector b = (-2, -1) can be written as follows;
b = -2·i - j, we have;
= √((-2)² + (-1)²) = √5
Therefore, we have;
The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)
Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2
The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))
Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.