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CaHeK987 [17]
3 years ago
12

What the right answer

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

a i think

Step-by-step explanation:

aivan3 [116]3 years ago
4 0

Answer:

A for the first one and c for the second

Step-by-step explanation:

sus

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Mr. Gephart is traveling from his house to the history museum. How many meters will he travel to the museum? The distance from h
snow_lady [41]

Answer: 6700 meters

Step-by-step explanation:

From the question given, we are informed that Gephart is traveling from his house to the history museum and that the distance from home to the history museum is six and seven-tenths kilometers.

In order to know the distance in meters

that he will travel to the museum, we have to multiply the convert the distance given in kilometers to meters. This will be:

1000 meters = 1 kilometer

Therefore, 6 7/10km = (6 7/10 × 1000m)

= 6 7/10 × 1000

= 67/10 × 1000

= 67 × 100

= 6700 meters

He'll travel 6700 meters to the museum.

7 0
3 years ago
Write by what rule you know the triangles are congruent, or write CNBD for "Cannot be determined." Segments and angles are congr
Triss [41]

RSM huh. I feel bad. I'm in this too.

4 0
3 years ago
Tyrese works each day and earns more money per hour the longer he works. Write a function to represent a starting pay of $20 wit
Anuta_ua [19.1K]

Answer:

B

Step-by-step explanation:

8 hours changes 24% increase pay.

24% means about +4.60

3 0
3 years ago
Read 2 more answers
An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"
7nadin3 [17]

Answer:

B: a = 1, b= 7, c = -2

Explanation:

\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}

Knowing This:

<u>solve for b</u>

  • -b = -7
  • b = 7

<u>solve for a</u>:

  • 2a = 2
  • a = 1

<u>solve c</u>:

  • b² - 4ac = 57
  • 7² - 4(1)(c) = 57
  • -4c = 57 - 49
  • -4c = 8
  • c = 8/-4 = -2
4 0
1 year ago
Read 2 more answers
Does (0,0) satisfy x+3y&gt;3
PtichkaEL [24]

\bf x+3y > 3\qquad \qquad (\stackrel{x}{0}~~,~~\stackrel{y}{0})\qquad \qquad 0+3(0) > 3\implies \stackrel{\stackrel{\textit{is this true?}}{\downarrow }}{0>3}\qquad nope!

4 0
3 years ago
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