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enot [183]
3 years ago
7

2(5-x)-4x-14-3(4x-4)

Mathematics
1 answer:
kozerog [31]3 years ago
8 0
2(5 - x) - 4x - 14 - 3(4x - 4) = 10 - 2x - 4x - 14 - 12x + 12 =
= 8 - 18x
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I need help on this one
tia_tia [17]
You need to come up with an array of answers for x and y that will be greater than 0.
x+4y>0. example if x is -1 and y is 1 will this be correct.
-1+(4*1)>0, -1+4>0. 3>0? Yes
if x is 1 and y is -1 then the equation becomes 1+(-4)>0 -3 is not>0 so it's not in the array
x could be -3 and y 1
You will plot a line to show all the answers.
i
8 0
4 years ago
Which expression completes the statement to form a true equation? 2 + 4² = ???
Anastaziya [24]

Answer:

3^2 +9

Step-by-step explanation:

Since 2+4^2 is 16+2 which is 18, you need to find the expression equivalent to 18. 25 doesn't work so eliminate that right away. 9^2=81 so that isn't right either. 2^3+9=17 so that is incorrect. Lastly, 3^2+9=18 so that is the correct answer.

8 0
3 years ago
Read 2 more answers
Help- i dont understand<br> Just 10 11 and 12 please!
katrin [286]
10. acute angles: 0
Right angles: 4
Obtuse angles: 0
Perpendicular lines: 0
Parallel lines: 2

11. Acute angles: 2
Right angles: 0
Obtuse angles: 1
Perpendicular lines: 0
Parallel lines: 0

12. H
6 0
3 years ago
Need help number the answers bye order plz
iragen [17]
OK so here it goes:
1a. 10³
1b. 10²
1c. 10(tiny 6)
1d. 10³
1e. 10(tiny6)
1f. 10(tiny 5)

2a. 400
2b. 640,000
2c. 5,400
2d. 5,301,000
2e. is it multipcation or addition
2f. 607,200
2g. 0.948
2h. 0.0094

3a) 0.02, 0.2, 2, 20, 200, 2000
3b) 3,400,000 ; 34,000; 340, 3.4, 0.034
3c) 85,700; 8,570; 857, 85.7, 8.57, 0.857
3d) 444, 4440, 44,400; 440,000; 4,400,000; 44,000,000
3e) 0.95, 9.5, 950, 95,000; 950,000; 9,500,000

Hope this helps.
6 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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