The **probability **that both the **first **digit and the **last **digit of the **three**-digit number are **even **numbers will be 0.4 or 40%.

<h3>What is probability?</h3>

Its basic premise is that something will **almost **certainly **happen**. The percentage of **favorable **events to the **total **number of **occurrences**.

The **number **of **three**-digit numbers with **distinct **digits can be **formed **using the **digits **1, 2, 3, 5, 8, and 9.

Then the **probability **that both the **first **digit and the **last **digit of the **three**-digit number are **even **numbers will be

Total event = ⁶C₃ = 20

Favorable event = 8 {218, 238, 258, 298, 812, 832, 852, 892}

Then we have

P = 8/20

P = 0.4

P = 40%

More about the **probability **link is given below.

brainly.com/question/795909

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