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3 years ago

Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1

1 answer:

5 0

$\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.$

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The point slope form of the eqaution of the line that passes through (-5,-1) and (10, -7) is y+7= -2/5 (x - 10) what is the stan

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Answer:

Step-by-step explanation:

The standard form of an equation of a line:

$Ax+By=C$

We have the equation in point-slope form:

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Convert it to the standard form:

$y+7=-\dfrac{2}{5}(x-10)$ multiply both sides by 5

$5y+35=-2(x-10)$ use the distributive property a(b + c) = ab + ac

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$5y=-2x-15$ add 2x to both sides

$2x+5y=-15$

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