Answer:
g(x) = 12x + 27
Step-by-step explanation:
Take a point in the f(x).
f(0) = 12(0) + 3
f(0) = 3
A point on f(x) is (0,3).
Move the point 2 units left. It will make the x-coordinate decrease by 2.
0 - 2 = -2
A point on g(x) is (-2,3).
Substitute the point and the same slope into the equation of a line. The slope did not change.
y = mx + b
3 = 12(-2) + b
3 = -24 + b
b = 3 + 24
b = 27
Rewrite g(x) using b = 27 and the same slope, m = 12.
g(x) = 12x + 27
Answer:
It is B. H = 3d
Step-by-step explanation:
I got it right :)
You know where the glacier is now, and how far it moves in
one year. The question is asking how close to the sea it will be
after many years.
Step-1 ... you have to find out how many years
Step-2 ... you have to figure out how far it moves in that many years
Step-3 ... you have to figure out where it is after it moves that far
The first time I worked this problem, I left out the most important
step ... READ the problem carefully and make SURE you know
the real question. The first time I worked the problem, I thought
I was done after Step-2.
============================
Step-1: How many years is it from 2010 to 2030 ?
(2030 - 2010) = 20 years .
Step-2: How far will the glacier move in 20 years ?
It moves 0.004 mile in 1 year.
In 20 years, it moves 0.004 mile 20 times
0.004 x 20 = 0.08 mile
Step-3: How far will it be from the sea after all those years ?
In 2010, when we started watching it, it was 6.9 miles
from the sea.
The glacier moves toward the sea.
In 20 years, it will be 0.08 mile closer to the sea.
How close will it be ?
6.9 miles - 0.08 mile = 6.82 miles (if it doesn't melt)
Answer:
Answer C is correct
Step-by-step explanation:
-200(3/4) = -600/4 = -150 ft
I suppose you mean to have the entire numerator under the square root?
We can use a trigonometric substitution to start:
Then for 
, 
; for 
, 
. So the integral is equivalent to
We can write
so the integral becomes
