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garik1379 [7]
3 years ago
13

The identification of critical information is a key part of the OPSEC process because: a) It is required by the JTF commander to

formulate operational COAs in the planning process. b) It is the fifth and final step of the OPSEC process. c) It focuses the remainder of the OPSEC process on protecting vital information rather than attempting to protect all unclassified information. d) None of the answers are correct. e) It focuses the OPSEC process on protecting all unclassified information.
Computers and Technology
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

The answer is "Option C".

Explanation:

It is the complete information regarding oriented motives, abilities, and strategies, in which opponents need to prepare or operate efficiently to ensure defeat or unreasonable implications toward favorable task achievement. In this information works on maintaining vital information for all the remaining part for the OPSEC form instead of protecting all classified data, and wrong choices can be described as follows:

  • In option a, It can't include, JTF commands that's why it is wrong.
  • In option b, The final stage is developed and apply, that's why it is incorrect.
  • In option e, It is wrong because it can't protect all unclassified data.
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Answer:

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 /*      type in bytes */

 

 #include <stdio.h>

 

   int main(void)

  {

  printf( "\nA char   is %d bytes", sizeof( char ));

  printf( "\nAn int   is %d bytes", sizeof( int ));

  printf( "\nA short   is %d bytes", sizeof( short ));

  printf( "\nA long   is %d bytes", sizeof( long ));

  printf( "\nA long long is %d bytes\n", sizeof( long long));

  printf( "\nAn unsigned char is %d bytes", sizeof( unsigned char ));

  printf( "\nAn unsigned int  is %d bytes", sizeof( unsigned int ));

  printf( "\nAn unsigned short is %d bytes", sizeof( unsigned short ));

  printf( "\nAn unsigned long is %d bytes", sizeof( unsigned long ));

  printf( "\nAn unsigned long long is %d bytes\n",

   sizeof( unsigned long long));

 printf( "\nA float   is %d bytes", sizeof( float ));

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return 0;

 }

2. #include<stdio.h>

int main(){

  int num,reverse_number;

  //User would input the number

  printf("\nEnter any number:");

  scanf("%d",&num);

  //Calling user defined function to perform reverse

  reverse_number=reverse_function(num);

  printf("\nAfter reverse the no is :%d",reverse_number);

  return 0;

}

int sum=0,rem;

reverse_function(int num){

  if(num){

     rem=num%10;

     sum=sum*10+rem;

     reverse_function(num/10);

  }

  else

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  return sum;

}

3.  

#include <bits/stdc++.h>  

 

using namespace std;  

/* Iterative function to reverse digits of num*/

int reversDigits(int num)  

{  

   int rev_num = 0;  

   while(num > 0)  

   {  

       rev_num = rev_num*10 + num%10;  

       num = num/10;  

   }  

   return rev_num;  

}  

 

/*Driver program to test reversDigits*/

int main()  

{  

   int num = 4562;  

   cout << "Reverse of no. is "

        << reversDigits(num);  

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   return 0;

4 0
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Answer:

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Explanation:

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Write a static method named lowestPrice that accepts as its parameter a Scanner for an input file. The data in the Scanner repre
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Answer:

Explanation:

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import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

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       String inputLocation = console.next();

       File inputFile = new File(inputLocation);

       Scanner in = new Scanner(inputFile);

       lowestPrice(in);

   }

   public static void lowestPrice(Scanner in) {

       double smallest = in.nextDouble();

       while(in.hasNextDouble()){

           double number = in.nextDouble();

           if (number < smallest) {

               smallest = number;

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3 years ago
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disa [49]

Answer:

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Explanation:

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3 years ago
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Answer:

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