Answer:
player1Wins = player1Losses = player2Wins = player2Losses = tieCount = 0
score1 = 10
score2 = 10
if score1>score2:
player1Wins=player1Wins+1
player2Losses=player2Losses+1
print("player1 wins")
elif score2>score1:
player2Wins=player2Wins+1
player1Losses=player1Losses+1
print("player2 wins")
else:
tieCount=tieCount+1
print("tie")
Explanation:
Since your indentation can not be understand what you give us, please try to do it as you see in the answer part.
Although it seems that this is a part of the code, it is normal that you get errors. However, since you keep track of the variables, it is better to initialize the variables that will keep the counts. Since initially, they are 0, you may set them as 0. Also, if you assign the values to the scores, probably you would not get any error. This way, you may test your code as I did.
Other than these, in the else part you do not need to write "score1=score2", because if score1 is not greater than score2 and if score2 is not greater than score1, this already implies that they are equal
<h3>Efficiency. Moreover, the same character in ASCII requires 7 bits, but EBCDIC required 8 bits. Therefore, ASCII is more efficient than EBCDIC.</h3>
import java.util.Scanner;
public class U3_L6_Activity_Two{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
int x = scan.nextInt();
int y = scan.nextInt();
if(x>=4|| ((y < 5) && ((x+y) < 7))){
System.out.println("pass");
}
}
}
I'm pretty sure this is what you're looking for. Best of luck.
