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galben [10]
3 years ago
8

"absmiddle" class="latex-formula">(b+4) = \frac{1}{2} }
Mathematics
1 answer:
VikaD [51]3 years ago
5 0
I hope this helps you 2 (B+4)=3 B+4=3/2 B=3/2-4 B=-5/2
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2. picking a number from 1 to 5 and choosing<br> the color red, white, or blue
bekas [8.4K]

Answer:

i would choose a 3 and color red

Step-by-step explanation:

i still don't understand the question tho

7 0
2 years ago
PLEASE HELP❗️❗️
Alexandra [31]

Answer:

A.irrational

Step-by-step explanation:

because 9 can be square to 3 but 11 cant be squared at all.

4 0
3 years ago
The pesticide diazinon is in common use to treat infestations of the German cockroach, Blattella germanica. A study investigated
cluponka [151]

Answer:

We conclude that there is no difference in the proportion of cockroaches that died on each surface.

Step-by-step explanation:

We are given that a study investigated the persistence of this pesticide on various types of surfaces.

After 14 days, they randomly assigned 72 cockroaches to two groups of 36, placed one group on each surface, and recorded the number that died within 48 hours. On the glass, 18 cockroaches died, while on plasterboard, 25 died.

<em>Let </em>p_1<em> = proportion of cockroaches that died on glass surface.</em>

<em />p_2<em> = proportion of cockroaches that died on plasterboard surface.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no difference in the proportion of cockroaches that died on each surface}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a significant difference in the proportion of cockroaches that died on each surface}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of cockroaches that died on glass surface = \frac{18}{36} = 0.50

\hat p_2 = sample proportion of cockroaches that died on plasterboard surface = \frac{25}{36} = 0.694

n_1 = sample of cockroaches on glass surface = 36

n_2 = sample of cockroaches on plasterboard surface = 36

So, <u><em>test statistics</em></u>  =  \frac{(0.50-0.694)-(0)}{\sqrt{\frac{0.50(1-0.50)}{36}+\frac{0.694(1-0.694)}{36}  } }

                               =  -1.712

The value of z test statistics is -1.712.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no difference in the proportion of cockroaches that died on each surface.

8 0
3 years ago
Sophie had a 15% off coupon for the book store. The original price of
tangare [24]

。ₓ ू ₒ ु ˚ Your answer would be 12.75! ˚ ू ₒ ु ₓ。

⭒❃.✮:▹ Considering 15% of 14.99 is 2.24, we would need to subtract that amount from 14.99.

14.99 - 2.24 = 12.75. ◃:✮.❃⭒

Hope this helps! ♡

3 0
2 years ago
Read 2 more answers
Answer for this one
REY [17]

Answer:

Step-by-step explanation:

The pH of solution a decreases, as the pH of solution B decreases as well.

7 0
3 years ago
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