Easy there on the caps, partner.
The nine, using the distributive property, distributes itself across the brackets, and so 9 times t is 9t and 9 times -1 is -9.
Therefore, 9(t-1) = 9t -9
Give them the same denominator.
19/30 is what you have left
Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
Answer:
58
Step-by-step explanation:
1. let x be the unknown number
2. make an expression
x + 26/12 = 7/1
3. cross multiply
x +26 × 1 = x + 26
12 × 7 = 84
x + 26 = 84
4. move variables on one side and numbers on other side of the equal sign
x + 26 = 84
- 26 -26
x = 58
