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EleoNora [17]
3 years ago
5

4a. If (11+x) is positive, but (4+x) is negative, what is one number that x could be?

Mathematics
1 answer:
sattari [20]3 years ago
8 0

Answer:

Step-by-step explanation:

x has to be equal to or less than a -5 to get (4 + x) to be a negative number.

x has to be equal to or greater than -10 for (11 + x) to be a positive number.

Therefore, any number between -10 and -5 will work.

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Subtract 8 feet from 9 yards, 1 foot.
Nostrana [21]

Answer: B

Step-by-step explanation:

I knew I would have 1 foot left so that made sure it wasn’t A then I knew that it the answer had to be in yards so I convert 8 feet into yards which becomes 2.7 so it’s not three which makes I’m not C. So 9 yards minus 2.7 yards would equal the answer B

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HELP<br> If you don’t know it then please don’t answer.
vovangra [49]

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3 years ago
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

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If any one could help me and explain how they would do this it would make my entire day it has to be a fraction please I can not
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