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Alenkinab [10]
3 years ago
5

Write the ratio 2/5 Over 3/5 in simplest form.

Mathematics
2 answers:
ruslelena [56]3 years ago
5 0
I think its 0.4 over 0.6
barxatty [35]3 years ago
5 0
Yeah it’s 0.4 over 0.6
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5^2+b^2=13^2 steps to solve
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b=12 or b=−12

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Which expression is equivalent to 9 x squared minus 2 y + 3 x squared minus 3 y?
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Answer:

The correct answer is 11 x squared + 2 y + x squared minus 3 y

Step-by-step explanation:

Just took the test on Edg. Hope it helps :)

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Which fraction has a terminating decimal as its decimal expansion?
alex41 [277]
'One third' as a decimal is 1 ÷ 3 = 0.333333..... ⇒ The decimal is recurring

'One fifth' as decimal is 1 ÷ 5 = 0.2 ⇒ The decimal terminates at the tenth value

'One seventh'  as decimal 1 ÷ 7 = 0.142857142857.... ⇒ The decimal is recurring for every digit between 1 and 7

'One ninth' as decimal 1 ÷ 9 = 0.111111.... ⇒ The decimal is recurring 

Answer: one fifth
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Evaluate the expression shown below and write your answer as a fraction in simplest form.​
Amiraneli [1.4K]

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1/2

Step-by-step explanation:

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HELP PLZZ will give brainliest <3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
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