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kupik [55]
2 years ago
6

What is the value of b that satisfies the equation below 3(b+4)-2(2b+3)=-4

Mathematics
2 answers:
zloy xaker [14]2 years ago
3 0

3(b+4)-2(2b+3)=-4 \\3b+12-4b-6=-4 \\-b=-10 \\b=10

The answer is C.

Hope this helps.

babunello [35]2 years ago
3 0
Answer: C) 10

Step 1: Rewrite equation

3(b+4)-2(2B+3)=-4

Step 2: Distribute

3(b+4)-2(2B+3)=-4

3b+12-4b-6=-4

Step 3: Combine like terms

3b+12-4b-6=-4

-b+6=-4

Step 4: Get -b alone on the left side

To do this we need to subtract 6 on both sides

-b+6=-4
-6 -6
______
-b=-10

Step 5: Making b positive

Since b cannot be a negative value we need to multiply both -b and -10 by -1 to make it positive

-b=-10

-1(-b)=-1(-10)

b=10

This is the final answer!

Hope this helps comment below for more questions :)
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Step-by-step explanation:

The bag has:

5 red marbles

8 blue marbles

4 yellow marbles

3 green marbles

A total of 5 + 8 + 4 + 3 = 20

You want to draw a red marble and then a blue marble.

The probability of drawing a red marble in your first attempt is the number of red marbles divided the total number of marbles:

P1 = 5/20  

now you want to draw a blue marble.

If you replace the red marble, you have 20 marbles again in the bag, then the probability of drawing a blue marble is:

P2 = 8/20

The joint probability is P = P1*P2 = (5/20)*(8/20) = 0.1

If you do not replace the red marble, you have 19 total marbles in the bag, then the probability of taking a blue marble is:

P2 = 8/19

The joint probability is:

P = P1*P2 = (5/20)*(8/19) = 0.105

The probability is slightly bigger if you do not replace the red marble.

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