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melisa1 [442]
3 years ago
5

At the amusement park, it is important for restrooms to be located in close proximity to the major attractions. The average dist

ance to a restroom should be 750 feet, give or take 50 feet. What is the range of distances that are permitted?
Mathematics
1 answer:
aksik [14]3 years ago
5 0

Answer:

700

Step-by-step explanation:

to find the range, you subtract the smaller number of the two numbers from the larger one. If there is more than two numbers, you subtract the smallest one of the group from the largest one in the group. In this situation, you do 750-50, which is 700.

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You walk into a store that is closing. the pants normally cost $60.00 but it is discounted 75% they are also taking additional 2
eimsori [14]

Answer:

The final cost of the pants is $ 12.

Step-by-step explanation:

Given that at a store that is closing the pants normally cost $ 60.00 but it is discounted 75%, and they are also taking an additional 20% off, to determine what is the final price for the pants, the following calculation must be performed:

100 - 20 = 80

(60 - (60 x 0.75)) x 0.80 = X

(60 - 45) x 0.80 = X

15 x 0.80 = X

12 = X

Thus, the final cost of the pants is $ 12.

7 0
3 years ago
Can anyone help with this ??
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Oof why do you think of the most important things to do in the future and the other is a great way to get the best out of the way and I have to say that I am not a fan of 45372
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What is the slope of the points (-2,7) and (2,-5)?<br> 4<br> -3<br> -12<br> 3
Dafna1 [17]

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-3

Step-by-step explanation:

Slope is equal to (-5-7)/(2-(-2)=-12/4=-3

6 0
3 years ago
Let f(x) = 3x - 10. Find the value of f(-3).
laiz [17]
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6 0
3 years ago
Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa
Artyom0805 [142]

Answer:

The height of the right trapezoid is   \frac{6}{5+\sqrt{3}}\ units

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+DH+HA

we have

P=6\ units

AB=BC=CH=HA=x ---> because is a square

substitute

6=x+x+CD+DH+x

6=3x+CD+DH -----> equation A

<em>In the right triangle CDH</em>

sin(30\°)=\frac{CH}{CD}

sin(30\°)=\frac{1}{2}

so

Remember  that CH=x

\frac{1}{2}=\frac{x}{CD}

CD=2x

tan(30\°)=\frac{CH}{DH}

tan(30\°)=\frac{\sqrt{3}}{3}

so

\frac{\sqrt{3}}{3}=\frac{x}{DH}

DH=x\sqrt{3}

substitute the values in the equation A

6=3x+CD+DH -----> equation A

CD=2x

DH=x\sqrt{3}

6=3x+2x+x\sqrt{3}

6=5x+x\sqrt{3}

6=x[5+\sqrt{3}]

x=\frac{6}{5+\sqrt{3}}\ units

5 0
3 years ago
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