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4 years ago

Please help!!!!!

Mathematics

2 answers:

vampirchik [111]4 years ago

8 0

Answer:

Step-by-step explanation:

Consider the quadratic equation, we have

$ax^2+bx+c=0$

Dividing the equation by a, we get

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

Put $\frac{c}{a}$ on the other side,

$x^2+\frac{b}{a}x=\frac{-c}{a}$

Add $(\frac{b}{2a})^2$ on both the sides,

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2$

completing the square, we have

$(x+\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2$

Now, solving for x,

$x+\frac{b}{2a}={\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}$

$x=\frac{-b}{2a}{\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}$

Multiply right side by $\frac{2a}{2a}$ ,

$x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}$

which is the required quadratic formula.

astraxan [27]4 years ago

8 0

Finish square of ax2 + bx + c = 0 to get the Quadratic Formula. Then youDivide both sides of the equation by A, so the coefficient of x2 is 1. Write again so the left side is in form x2 + bx.

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Which three lengths could be the lengths

Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

$4+8=12$

$4+8$

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

$13+11=24$

$13+11>23$

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

$5+12=17$

$5+12$

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

$8+16=24$

$8+16$

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

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3 years ago

If 60 equals twice a number added to itself, find the number.

AlladinOne [14]

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4 years ago

What is the equation of this line in standard form? −8x+7y=25 −9x+8y=−23 −8x+9y=−23 −8x+9y=23

kvasek [131]

<span>−8x+7y=25 is already in standard form, altho some people would prefer to re-write it as

</span><span>−8x+7y-25 = 0.

You have shared 4 equations here. Next time, please separate them with commas or semi colons, or type just 1 equation per line, for increased clarity. Thanks.</span>

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4 years ago

Factor the equation. 2x+13x-15

dmitriy555 [2]

Answer:

(2x+15)(x−1)

Step-by-step explanation:

Factor 2x2+13x−15

2x2+13x−15

=(2x+15)(x−1)

Here is the answer good sir

7 0

4 years ago

Read 2 more answers

How do I find dy/dx of the following?

Pachacha [2.7K]

Answer:

$\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}$

Step-by-step explanation:

$y \ = \ x^{3} \ - \ \displaystyle\frac{1}{\sqrt{x}} \ + \ \displaystyle\frac{3}{x^{4}} \\ \\ y \ = \ x^{3} \ - \ x^{-\frac{1}{2}} \ + \ 3x^{-4} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{3 \ - \ 1} \ - \ \left(-\displaystyle\frac{1}{2}\right)x^{-\frac{1}{2} \ - \ 1} \ + \ \left(-4 \ \times \ 3\right)x^{-4-1}$

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2 years ago