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Natali5045456 [20]
4 years ago
8

Please help!!!!!

Mathematics
2 answers:
vampirchik [111]4 years ago
8 0

Answer:

Step-by-step explanation:

Consider the quadratic equation, we have

ax^2+bx+c=0

Dividing the equation by a, we get

x^2+\frac{b}{a}x+\frac{c}{a}=0

Put \frac{c}{a} on the other side,

x^2+\frac{b}{a}x=\frac{-c}{a}

Add (\frac{b}{2a})^2 on both the sides,

x^2+\frac{b}{a}x+(\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2

completing the square, we have

(x+\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2

Now, solving for x,

x+\frac{b}{2a}={\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}

x=\frac{-b}{2a}{\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}

Multiply right side by \frac{2a}{2a},

x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}

which is the required quadratic formula.

astraxan [27]4 years ago
8 0
Finish square of ax2 + bx + c = 0 to get the Quadratic Formula. Then youDivide both sides of the equation by A, so the coefficient of x2 is 1. Write again so the left side is in form x2 + bx.
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