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2 years ago

Find the solution set

1 answer:

7 0

M1= -5 , m2 = 5 inorder to get this you move the constant to the right take the root of both sides separate the solutions and you should get m1= -5, m2 =5

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Whats the prime factors of 69

SOVA2 [1]

Answer:

3 times 23 is your prime factorization. hope this helps!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If f(x) = 2x2 and g(x)= x2 + 2x, which expression represents f(g(x))?

andre [41]

Answer:

f(g(x)) = 2(x^2 + 2x)^2

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Step-by-step explanation:

Given;

f(x) = 2x^2

g(x) = x^2 + 2x

To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).

f(g(x)) = 2(g(x))^2

f(g(x)) = 2(x^2 + 2x)^2

Expanding the equation;

f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)

f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)

f(g(x)) = 2(x^4 + 4x^3 + 4x^2)

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Hope this helps...

7 0

2 years ago

-2x - 5y = 13 2x - 5y =17

Flura [38]

{-2x-5y=13

{2x-5y=17 (+)

-2x+2x-5y-5y=13+17

-10y=30 /:(-10)

y=-3

2x-5y=17

2x-5*(-3)=17

2x+15=17

2x=2

x=1

Solution: (1; -3)

6 0

2 years ago

An automobile dealership gives a discount of 8% if payment os made in cash. How much would a $17,500 car cost if the payment wer

Zarrin [17]

Answer:

16100

Step-by-step explanation:

17500×0.92=16100

8 0

3 years ago

List the sides of each triangle from shortest to greatest

Lelechka [254]

In every triangle, the largest side, is opposite the largest angle.

Also, the smallest side, is opposite the smallest angle.

a. $70^o\ \textgreater \ 60^o\ \textgreater \ 50^o$ so $|RQ|\ \textgreater \ |PR|\ \textgreater \ |PQ|$ ,

because RQ is opposite angle P, the largest,
PR is opposite angle Q , the middle
and PQ is opposite angle R, the smallest.

Greatest side: RQ

b. The sum of the measures of the interior angles of any triangle is 180°,

so

$m(A)+m(B)+m(C)=180^o\\\\50^o+45^o+x=180^o\\\\x=180^o-50^o-45^o=85^o$

thus, m(C) is the largest angle. This means the largest side is the side AB.

Answers:

a) RQ
b)AB

8 0

2 years ago