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TiliK225 [7]
3 years ago
7

A student loan you took out is due in 3 years and requires repayment of $3,000. To pay off the loan, you set aside money in an a

ccount that pays 7% interest.
To meet your obligation, how much money do you need to deposit in the account?
Mathematics
1 answer:
damaskus [11]3 years ago
7 0

Answer:

P = $2448.89

P ~= $2,449

He need to deposit $2,449

Step-by-step explanation:

Given:

Interest rate r= 7% = 0.07

Number of years n = 3 years

Future value that should be meet A = $3000

We need to calculate the initial investment (Principal P). Using the compound interest formula:

A = P(1+r)^n

P = A/(1+r)^n

Substituting the values of A, r, n, we have;

P = 3000/(1+0.07)^3

P = $2448.89

P ~= $2,449

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I need help please ^^
Vaselesa [24]

Answer:

  see below

Step-by-step explanation:

Usually, we're concerned about the relationship of y to x. Here, the question is asking you to consider the relationship of x to y.

The easiest way to find the answer to this one is to check the given explanations to see which is true. You can pretty much ignore the first row of the table and just look at the second row where x=5 and y=15.

  • it is NOT TRUE that x is 3 times y (5 is not 3 times 15)
  • it is TRUE that x is 1/3 of y (5 is 1/3 of 15)
  • it is NOT TRUE that x is 5 times y (5 is not 5 times 15)
  • it is NOT TRUE that x is 1/5 of y (5 is not 1/5 of 15)

_____

If you know your multiplication tables, you know that 15 = 3×5, so ...

  5 = 15/3

  5 = (1/3) × 15

The relationship of these numbers should not be a mystery.

4 0
3 years ago
Can you help me please I don't understand. ​
Dimas [21]

B. A and b parrel never touch

C. 44

D.136

E.44

Hope this helps a little

8 0
3 years ago
Which equation matches the graph of the greatest integer function given
QveST [7]
The answer is A. y = [x] -2
5 0
2 years ago
Where is the most optimal position to send your bean bag in relation to opponent's bean bag?​
Stella [2.4K]

Answer:

right side

Step-by-step explanation:

7 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
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