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Zolol [24]
3 years ago
6

If 2 angles are supplementary,then the angles _________

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0
Hey there! :)

The answer is A.

Supplementary angles are angles that have a total sum of 180 degrees.

Hope this helps! :)
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-3 5/12 divided 2 please help
finlep [7]

Answer:

on the file:

:)

8 0
3 years ago
I need help with number 1-4 I don’t understand..
Karo-lina-s [1.5K]

Answer:

  1. 109°, obtuse
  2. 131°, obtuse
  3. 53°, acute
  4. 124°, obtuse

Step-by-step explanation:

You are exected to know the relationships of angles created where a transversal crosses parallel lines.

  • Corresponding angles are equal (congruent).
  • Adjacent angles are supplementary, as are any linear pair.
  • Opposite interior (or exterior) angles are equal (congruent).

The appearance of the diagram often gives you a clue.

You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.

1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.

2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.

3. Opposite interior angles are equal, so w will be 53°. It is acute.

4. Corresponding angles are equal, so x will be 124°. It is obtuse.

8 0
3 years ago
I need help with this
yanalaym [24]

Answer:

(-2, -4)

Step-by-step explanation: because its going backwards it should be a negative slope :)

I'm sorry if I'm wrong  but i hope this helps :)

6 0
2 years ago
Matthew bought 12 roses for his mother. Exactly 1 of the roses were white. How many of the roses were white?
insens350 [35]
<h3>hello!</h3>

What is \sf{\displaystyle\frac{1}{4}} of 12?

In order to find it, we should divide 12 by 4:-

3

Now, solve our word problem:-

Matthew bought 12 roses. \sf{\displaystyle\frac{1}{4} } of these roses were white.

And we already know how to solve this problem :)

Hence,

\bigstar{\boxed{\pmb{3~of~the~roses~were~white}}}

<h3>note:-</h3>

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

8 0
2 years ago
Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.
natta225 [31]

The ODE is linear:

y'=x^4-\dfrac yx

y'+\dfrac yx=x^4

Multiplying both sides by x gives

xy'+y=x^5

Notice that the left side can be condensed as the derivative of a product:

(xy)'=x^5

Integrating both sides with respect to x yields

xy=\dfrac{x^6}6+C

\implies y(x)=\dfrac{x^5}6+\dfrac Cx

Since y(1)=1,

1=\dfrac16+C\implies C=\dfrac56

so that

\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}

4 0
3 years ago
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