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3 years ago

What is the equation of a circle with a center (3, 3) and a area of 219π

Mathematics

1 answer:

katrin2010 [14]3 years ago

8 0

Answer:

I don't know I'm really sorry please don't be angry

and if you want my social media cause your angry I'll give

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Please help me!<br><br> 3x + 2 > x - 8 <br><br> (please show work)

pychu [463]

Next time, please include the instructions: "Solve for x:"

Starting with 3x + 2 > x - 8

subtract 2 from both sides, and also subtract x from both sides, obtaining

2x > - 10

Divide both sides by 2: x > -5

6 0

3 years ago

Read 2 more answers

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KengaRu [80]

for the health inspector is 4x7=28 days and the fire inspector 12x4=48 days. the last question is confusing?

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4 years ago

What is -3(4x+8)/3(-2)

Nady [450]

Answer:

2x+4

Step-by-step explanation:

8 0

3 years ago

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Find all possible values of the expression 1/y if: .125

34kurt

Answer:

The possible values for 1/y of the expression 0.125 < y < 0.25 are in the range

4 < 1/y < 8

Step-by-step explanation:

The given information are;

The range of values of y are 0.125 < y < 0.25, therefore, we have;

The boundaries of the function, y are 0.125 and 0.25

The inverse of the boundaries of the function, y are 1/0.125 = 8 and 1/0.24 = 4

Therefore;

The limits of the inverse of the function y are ;

The inequality that represents 1/y is therefore;

1/0.25 < 1/y < 1/0.125 or 4 < 1/y < 8

The possible values of 1/y for the expression 0.125 < y < 0.25 are therefore;

4 < 1/y < 8.

8 0

3 years ago

What is the result of isolating x2 in the equation below?(x + 1)2 + ( -8)2 =9A. x2 = -y2 - 2x +16y - 56B. x2 = y2 +2x+16y +56C.

Anit [1.1K]

The expression we have is:

$(x+1)^2+(y-8)^2=9$

Step 1. Use the binomial square formula:

$(a+b)=a^2+2ab+b^2$

Applying this formula to the first binomial squared:

$x^2+2x+1+(y-8)^2=9$

Step 2. Apply the formula for the square of a binomial to the second binomial:

$x^2+2x+1+y^2+2(y)(-8)+(-8)^2^{}=9$

In this case, we have some operations to solve before we move on to isolating x. So we solve the operations:

$x^2+2x+1+y^2-16y+64^{}=9$

Step 3. Move the terms that are not x squared to the right side of the expression. Remember that when we move one term from one side of the equation to the other, the term must change its sign. We get the following:

$x^2=9-2x-1-y^2+16y-64$

Step 4. Combine like terms and arrange terms in order from the greatest exponent to the lowest and leave the independent term at the end:

$x^2=-y^2-2x+16y-56$

And that is the final result, which is option A.

Answer: Option A.

3 0

2 years ago