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algol [13]
3 years ago
15

What is the answer for the attached picture

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
It should be 13 as well
Because the arc length of CDE and ABCD are both 90 degrees. They share 20 degrees from arc CD and they already both have 70 degrees. So if the arc length is equal, the corresponding chords should be equal too.
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The answer for the simplest form
grigory [225]
The simplest form is 11/24.
3 0
3 years ago
Help me with this plzzz
adell [148]

Answer:

2/3

Step-by-step explanation:

Everytime the line moves over 3 it goes up 2, so the run is 3 and rise is 2. It is written in rise over run.

4 0
2 years ago
Read 2 more answers
Can anyone please help me :)
Solnce55 [7]

Answer:

5 to the 15th power.

Step-by-step explanation:

PEMDAS requires us to do parenthesis, then exponents, and then division. Let's do 5³. 5x5x5 is equal to 125. Now, we find 125 to the ninth power. According to my calculations, 125 to the ninth power is equal to 7,450,580,596,923,828,125. Now, we find 5 to the twelfth power, which, according to my calculations, is 244,140,625. Now, we solve. According to my calculations, 7,450,580,596,923,828,125/244,140,625 is equal to 30,517,578,125. 30,517,578,125 is equivalent to 5 to the 15th power. That means that the second option is correct. I hope this helps!

3 0
3 years ago
(x^3 + 5)(2x – 1)<br>(x^2 – 4)(x^2 + 4)​
earnstyle [38]

Answer:

x^{3} +x^{2} +1

Step-by-step explanation:

5 0
3 years ago
The heights in inches of orangutans Are normally distributed with a population standard deviation of 3" and an unknown populatio
CaHeK987 [17]

Answer: The 95% confidence interval is approximately (55.57, 58.43)

======================================================

Explanation:

At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.

The sample size is n = 17

The sample mean is xbar = 57

The population standard deviation is sigma = 3

The lower bound of the confidence interval is

L = xbar - z*sigma/sqrt(n)

L = 57 - 1.960*3/sqrt(17)

L = 55.5738905247863

L = 55.57

The upper bound is

U = xbar + z*sigma/sqrt(n)

U = 57 + 1.960*3/sqrt(17)

U = 58.4261094752137

U = 58.43

Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.

7 0
3 years ago
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