Answer:Magnitude of voltage is 41.9963 volts
Step-by-step explanation:
Given that current I =5.772-5.323i mA
and impedance, Z=3.342+4.176i kilo ohms
Then voltage in the circuit = IZ
![=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}](https://tex.z-dn.net/?f=%3D%285.772-5.323i%29X10%5E%7B-3%7DX%283.342%2B4.176i%29X10%5E%7B3%7D)
![V=(5.772-5.323i)X(3.342+4.176i)](https://tex.z-dn.net/?f=V%3D%285.772-5.323i%29X%283.342%2B4.176i%29)
![V=19.290024+24.103872i-17.789466i-23..5148848i^{2}](https://tex.z-dn.net/?f=V%3D19.290024%2B24.103872i-17.789466i-23..5148848i%5E%7B2%7D)
![V=41.518892+6.314406i](https://tex.z-dn.net/?f=V%3D41.518892%2B6.314406i)
Magnitude of V = ![\sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts](https://tex.z-dn.net/?f=%5Csqrt%7B41.518892%5E%7B2%7D%20%2B6.314406%5E%7B2%7D%20%7D%3D%5Csqrt%7B1763.6901%7D%3D41.9963volts)
<span>£19,500
10*37.5*52 =</span>£19,500
Answer: E) 450g and F) 100g
Step-by-step explanation:
A pound is approximately <em>0.4535 kilogrammes</em>, so <em>453,5 grammes</em>. With this information, we can determine that answers E (450 grammes) and F ( 100 grammes) are the only correct ones.
<u>Top row - Left Row :</u>
Order : Left to Right
{11.7 - below(negative)} , {11.6 - below(negative)} , {12 - exactly filled} , {12.2 - above(positive)}
<u>Middle Row </u>:
Order : Left to Right
{11.1 - below(negative)} , {11.2 - below(negative)} , {11.9 - below(negative)} , {12.5 - above(positive)}
<u>Right Row </u>:
Order : Left to Right
{12 - exactly filled} , {11.4 - below(negative)} , {11.5 - below(negative)} , {10.8 - below(negative)}
Answer:
The standard form of the equation of a circle is,
(x - h)² + (y - k)² = r²
where the center is at (h, k) and its radius is r. Not sure what the equation would be sorry.
Step-by-step explanation: