No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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Answer:
Step-by-step explanation:
The ratio of pencils to erasers is
Convert the ratio to a fraction.
The fraction is now pencils to erasers.
The fraction of the number of erasers to pencils is:
Go 3+4+2 to determine for 1 row and then multiply that by 64 so 576
Answer:
Step-by-step explanation:
If k is the number of classes and n is the number of observations, then for number of classes we should select the smallest k such that 2^k > n.
<u>We have n = 50 and:</u>
- 2^5 = 32 < 50
- 2^6 = 64 > 50
As per above described 2 to k rule, we are taking k = 6.
So 6 classes should be used.
