Answer:
- Volume of cubiod= 108 in³
- TSA of cubiod = 168 in²
Step-by-step explanation:
<u>Given: </u>
Dimensions of cubiod :
- Length = 9 in.
- Breadth = 6 in.
- Height = 2 in.
<u>To Find:</u>
- Volume and Total surface area
<u>Solution</u>:
We know that,
So,
→ Volume = 9 × 6 × 2
→ Volume = 54 × 2
→ Volume = 108 in³
And,
- TSA of cubiod = 2(lb + bh + hl)
Substituting the values, we get:
→ TSA = 2(9 × 6) + (6 × 2) + (9 × 2)
→ TSA = 2(54 + 12 + 18)
→ TSA = 2 × 84
→ TSA = 168 in²
Hence,
- Volume of cubiod= 108 in³
- TSA of cubiod = 168 in²
Answer:
1/6
Step-by-step explanation:
i used a calculator
9514 1404 393
Answer:
2/5, 7/15, 8/15, 3/5, 2/3
Step-by-step explanation:
If these fractions are expressed with a common denominator, that would be 3×5 = 15. Then the given fractions are 1/3 = 5/15, and 4/5 = 12/15. The numerators 5 and 12 differ by 7, so we can easily choose 5 fractions in that range:
6/15 = 2/5
7/15
8/15
9/15 = 3/5
10/15 = 2/3
_____
<em>Alternate solutions</em>
There is no requirement for the fractions to be written any particular way or with any particular spacing. The limits in decimal are 1/3 = 0.3333...(repeating) and 4/5 = 0.8. We could choose the decimal fractions ...
0.34, 0.40, 0.50, 0.60, 0.70
or
0.41, 0.52, 0.63, 0.74, 0.79
Answer:
Perimeter: 16x + 16
Area: 40x + 15
Step-by-step explanation:
Remember, the perimeter is the sum of all the sides of a figure, it can be found by adding up all the sides. The area is the space within the figure, in the case of a quadrilateral can be found by multiplying the length by the width. Finally, in a rectangle, the opposite sides are congruent, parallel, and intersect in 90degree (right) angles.
Using this,
1. Find the perimeter
Since opposite sides are congruent, there will be two sides with a measure of ( 8x + 3 ), and two sides with the measure of 5. Hence the sum of all the sides would be
8x + 3 + 8x + 3 + 5 + 5
Add them together,
16x + 16.
The perimeter of the figure is 16x + 16
2. Find the area,
To find the area of a rectangle, multiply the length by the width.;
( 8x + 3 ) * 5
Distribute:
40x + 15
The area of the figure is 40x + 15
