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oksano4ka [1.4K]

3 years ago

13

13 gallons of water are used to completely fill 3 fish tanks. If each tank holds the same amount of water, how many gallons will

each tank hold? Express your answer as a mixed number.

1 answer:

Pepsi [2]3 years ago

7 0

Answer:

4 1/3

Step-by-step explanation:

12/3=4

1/3+4=4 1/3

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Sveta_85 [38]

Answer: 15,375 inches

Step-by-step explanation: If there are 123 inches in each group, and there are 125 groups, it is a multiplication operation.

123 × 125 = 15375

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6 0

3 years ago

Hey can you please help me posted picture of question

svet-max [94.6K]

If we observe the graph we can see that the curve crosses the x-axis at the following points: 1, 3, and 5
This means x = 1, x = 3 and x = 5 are the roots of the polynomial and x - 1, x - 3 and x - 5 are the factors of the polynomial.

We can express the polynomial as the product of its factors. So the polynomial will be (x-1)(x-3)(x-5)

The correct answer to this question is option A

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3 years ago

Read 2 more answers

Determine if they are congruent. State how they are.

Doss [256]

$\huge \bf༆ Answer ༄$

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$\textsf{Not enough information }$

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2 years ago

Whats the decimal equivalent of 1\4

Vesnalui [34]

The decimal equivalent of 1/4 is 0.25.

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3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago