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quester [9]
3 years ago
12

Question number 5 who can help me out

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer: 3,484.

Given;

P = $13,400

R =6½% => 13/2 ( Changing to improper fraction).

T = 4 years.

Using, I = PRT/100

I= <em>1</em><em>3</em><em>,</em><em>4</em><em>0</em><em>0</em><em>×</em><em>1</em><em>3</em><em>×</em><em>4</em><em>/</em><em>2</em><em>×</em><em>1</em><em>0</em><em>0</em>

I =<em>6</em><em>9</em><em>6</em><em>,</em><em>8</em><em>0</em><em>0</em><em>/</em><em>2</em><em>0</em><em>0</em>

<em>I</em><em>=</em><em><u>3</u></em><em><u>,</u></em><em><u>4</u></em><em><u>8</u></em><em><u>4</u></em>

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slavikrds [6]

Given inequality -3(4-6x) < x+5.

We have -3 in front of Parenthesis.

That represents multiplication of -3 and Parenthesis.

The multiplication of Parenthesis could be done by applying distributive property.

On distributing, we get

-12+18x < x+5

x is added on right side of the inequality. The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get

-12+18x-x < x-x+5

-12+17x < 5

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So, we need to apply addition property of equality, we need to add 12 on both sides, we get

-12+12+18x < x+5+12

17x < 17

We need to get rid 17 from left side. So we need to apply division property of equality.

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8 0
3 years ago
What is 3540 divided by 6?
adoni [48]
3540/6 = 590

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3 years ago
What is the approximate circumference of the circle shown below?
krek1111 [17]

Answer:

\boxed{\sf 43.35 \ cm}

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5 0
3 years ago
Read 2 more answers
Rearrange<br> C=d+2/3<br> to make d the subject.
raketka [301]

Answer:

d = C - 2/3

Step-by-step explanation:

Subtract 2/3 from both sides of the equation:

C = d + 2/3

-2/3     -2/3

-----------------

C - 2/3 = d

3 0
3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0
3 years ago
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