Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² = 
t = 
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² = 
t = 
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² = 
t = 
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
Let d be distance travelled when they are level , and t = time that nora took to get level with mason
for Nora
6 = d/t
d = 6t
for Mason
5 = d / (t + 35)
d = 5 ( t + 350
so 6t = 5(t + 35)
solve for t
Answer:
Step-by-step explanation:
175 is the answer I don’t feel like working it out
Rewrite the equation below in standard form.
-3x+6y=12
C. -x+2y=4
if you take each term and divide them by 3 you will get the c