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Brilliant_brown [7]
3 years ago
11

The table shows the steps for solving the given inequality for x.

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

Given inequality -3(4-6x) < x+5.

We have -3 in front of Parenthesis.

That represents multiplication of -3 and Parenthesis.

The multiplication of Parenthesis could be done by applying distributive property.

On distributing, we get

-12+18x < x+5

x is added on right side of the inequality. The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get

-12+18x-x < x-x+5

-12+17x < 5

Now, we need to get rid -12 from left side.

So, we need to apply addition property of equality, we need to add 12 on both sides, we get

-12+12+18x < x+5+12

17x < 17

We need to get rid 17 from left side. So we need to apply division property of equality.

On dividing both sides by 17, we get

17x/17 < 17/17

x<1.

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4.5.36
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Answer:

Step-by-step explanation:

Given function is h(t) = -16t² + 1500

a). For h(t) = 1000 feet,

   1000 = -16t² + 1500

   1000 - 1500 = -16t² + 1500 - 1500

   -500 = -16t²

    t² = \frac{500}{16}

    t = \sqrt{31.25}

    t = 5.59 sec

b). For h(t) = 940 feet,

   940 = -16t² + 1500

   940 - 1500 = -16t² + 1500 - 1500

   -16t² = -560

   t² = \frac{-560}{-16}

   t = \sqrt{35}

   t = 5.92 sec

c). For domain and range of the function,

  When the jumper comes down to the ground,

   h = 0

   0 =-16t² + 1500

   t² = \frac{1500}{16}

   t = \sqrt{93.75}

   t = 9.68 sec

  Since, x-values on the graph vary from x = 0 to x = 9.68,

  Domain : [0, 9.68]

  Vertex of the quadratic function: (0, 1500)

  Since, coefficient of the highest degree term is negative, parabola will open downwards.

  Therefore, y-values of the function will vary in the interval y = 0 to y = 1500

  Range: [0, 1500]  

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3 years ago
(05.02 LC)
Anvisha [2.4K]
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  • tany=s/t

\\ \tt\longmapsto cosy=\dfrac{siny}{tany}

\\ \tt\longmapsto cosy=\dfrac{s/8}{s/t}

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Answer:

Step-by-step explanation:

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Rewrite the equation below in standard form.
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Rewrite the equation below in standard form.
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