Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by .
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.
b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.
c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.
I’m assuming the 2’s are supposed to be exponents so you’re gonna to combine 7m^2 and 4m^2 to get 11m^2 so you’re answer would be
11m2+3m
You dint know the value of M so you can’t solve it, especially because there’s no equal sign with a number or expression/equation after it.
Answer:
y=17/4 - 3x/4
Step-by-step explanation: