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Alexxx [7]
3 years ago
7

Using suitable property solve -3/4*2/3+3/4*-5/6

Mathematics
2 answers:
saveliy_v [14]3 years ago
4 0

Answer:

Step-by-step explanation:

Distributive property

\frac{-3}{4}*\frac{2}{3}+\frac{3}{4}*\frac{-5}{6}\\\\=\frac{-3}{4}*[\frac{2}{3}+\frac{5}{6}]\\\\=\frac{-3}{4}*[\frac{2*2}{3*2}+\frac{5}{6}]\\\\=\frac{-3}{4}*[\frac{4}{6}+\frac{5}{6}]\\\\=\frac{-3}{4}*[\frac{4+5}{6}]\\\\=\frac{-3}{4}*\frac{9}{6}\\\\=\frac{-1}{4}*\frac{9}{2}\\=\frac{-9}{8}}\\\\=-1\frac{1}{8}

REY [17]3 years ago
3 0

Answer: The answer is -1/8

Step-by-step explanation:

3/4*2/3+3/4*-5/6

3 is cancelled out with 3, 4 with 2, 3 with 6

1/2-5/8

take the L.C.M

4(1)-1(5)/8

4-5/8

=-1/8

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bearhunter [10]

Answer:

Multiplier = 1.75x (7/4).

7/8 cups butter, 4 and 3/8 ounces chocolate, 1 and 3/4 cups sugar, 7/8 teaspoons vanilla, 3 and 1/2 eggs (4 if rounded!), 1 and 5/16 cups flour.

Step-by-step explanation:

The ingredient list is for 16 brownies, but you need to make 28. This means you have to make 1.75x the amount (28/16), so all ingredient quantities need to be multiplied by 7/4 (1.75 in fraction form).

Butter: 1/2 * 7/4 = 7/8 cups

Chocolate: 5/2 * 7/4 = 4 and 3/8 ounces

Sugar: 1 * 7/4 = 1 and 3/4 cups

Vanilla: 1/2 * 7/4 = 7/8 teaspoons

Eggs: 2 * 7/4 = 3 and 1/2 eggs (if rounded, 4, as 3.5 rounds up)

Flour: 3/4 * 7/4 = 1 and 5/16 cups

3 0
3 years ago
Please help and is #2 right?????
Rudiy27
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4 0
3 years ago
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Find the ratio of p to S <br><br> 3p=8s
vodomira [7]
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3 years ago
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2.36 to the nearest whole number
Igoryamba

Answer:

2

Step-by-step explanation:

2.36 would need to be at least 2.50 or higher to be rounded to 3 so we round down to 2

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7 0
3 years ago
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It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

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3 years ago
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