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3 years ago

What is the answer to : 7(5n-8)+6(4+6n)

Mathematics

2 answers:

stealth61 [152]3 years ago

8 0

I cant see the picture so I am just going by what u wrote...
7(5n - 8) + 6(4 + 6n) =
35n - 56 + 24 + 36n =
71n - 32 <===

irinina [24]3 years ago

6 0

7(5n - 8) + 6(4 + 6n)

= 35n - 56 + 24 + 36n

= 71n - 32

Hence, the answer is 71n - 32.

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Helpppppppppp mehhhhh plz

Goshia [24]

Let's start off with a simple y-intercept form.

y=mx + b
b represents the y intercept so we can substitute it with 2.
y = mx + 2
the point we are given, (1,1) is really just an x and y value. We can also substitute this into the equation.
y = x + 2

Now that we have some type of equation, we can convert it to the form shown in the answer choices by subtracting y from both sides.
0 = x - y + 2
Hope this helps!

4 0

3 years ago

The Hiking Club plans to go camping in a State park where the probability of rain on any given day is 2/3. What is the probabili

Aleksandr [31]

Answer:

19.75%

Step-by-step explanation:

Since we are trying to find the probability for a sequence of events then we need to multiply the probability of each event happening separately from each other. Since the probability of it raining on a single day is 2/3 we need to multiply this value with itself 4 times (one for each day).

2/3 * 2/3 * 2/3 * 2/3 = 16/81 or 0.1975 or 19.75%

Therefore the probability would be 16/81 or 0.1975 or 19.75%

3 0

3 years ago

Find the midpoint of the line segment joining the points (-2, -1) and (-8,12).

SCORPION-xisa [38]

x¹ = -2 x² = -8

y¹ = -1 y² = 12

Using midpoint formula,

M = ( x¹ + x²/2 ,y¹ + ý²/2)

or,M ={ -2+(-8)/2 , (-1) +12/2}

or, =( -10/2 , 11/2)

:M = ( -5 , 11/2)

6 0

3 years ago

Which of the following is an example of conditional probability.

Papessa [141]

B
the probability of an event ( A<span> ), given that another ( </span>B<span> ) has already occurred.
</span>

6 0

4 years ago

Read 2 more answers

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard

avanturin [10]

Answer:

There is a 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean \mu and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard deviation of 2503 miles.

This means that $\mu = 33208, \sigma = 2503$ .

What is the probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct?

This is the pvalue of Z when $X = 33208+633 = 33841$ subtracted by the pvalue of Z when $X = 33208 - 633 = 32575$

By the Central Limit Theorem, we have t find the standard deviation of the sample, that is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{2503}{\sqrt{49}} = 357.57$

X = 33841

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{33841 - 33208}{357.57}$

$Z = 1.77$

$Z = 1.77$ has a pvalue of 0.9616

X = 32575

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{32575- 33208}{357.57}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 0.9616 - 0.0384 = 0.9232 = 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

4 0

4 years ago