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Yuri [45]
3 years ago
14

A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t2 + 608t.After how many seconds d

oes it reach its maximum height?
Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0
The question is asking you to find the axis of symmetry, which is the x-value of the vertex. In order to do that you need to factor the function to find the zeros and add the zeros together and divide by two to find the axis of symmetry.
y=-16x^2+608x
y=-16x(x-38)
Zeros: x=0 and x=38
38/2=19
Therefore it takes 19 seconds for the projectile to reach its maximum height.
Hope this helps!
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Step-by-step explanation:

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<h2><u>Answer with explanation</u>:</h2>

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As per given , we have

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Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given \sigma=1 , so we perform one-tailed z-test.

Test statistic : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

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n= sample size

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For n= 18 , \overline{x}=4.50 , \sigma=1 , \mu =4, we have

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[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

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