3 years ago

2 1/2kg cost £2.50. How much for 1kg?

Mathematics

2 answers:

TEA [102]3 years ago

6 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Figure out what you would need to do to get from 2.5kg to 1kg

You would need to divide by 2.5

Just divide the cost by this value:

2.5/2.5 = 1

1kg would cost £1.00

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Talja [164]3 years ago

6 0

The answer would be

1kg= £1.00

You might be interested in

Find the distance between the points (a, 0) and (0, b). StartRoot (a minus b) squared EndRoot StartRoot a squared + b squared En

borishaifa [10]

Answer:

square root of (a^ + b^) or the option b

Step-by-step explanation:

its right on edge 2020

hope this helped :)

5 0

2 years ago

Read 2 more answers

Solve for t: if a≠−b<br> t + <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bat%7D%7Bb%7D" id="TexFormula1" title="\frac{at}{b}" alt

prohojiy [21]

Answer:

$t=\frac{b}{b+a}$

Step-by-step explanation:

we have

$t+\frac{at}{b}=1$

Solve for t

That means ----> Isolate the variable t

Multiply by b both sides to remove the fraction

$bt+at=b$

Factor the variable t in the left side

$t[b+a]=b$

Divide by (b+a) both sides

$t=\frac{b}{b+a}$

4 0

3 years ago

The graph of a system of equations with the same slope will have no solutions. (1 point)

Viefleur [7K]

I don’t really get what you’re asking here but a system of 2 parallel lines has no solution, and a system of 2 parallel lines is called inconsistent.

3 0

3 years ago

Are these ratios equivalent?

Aliun [14]

Answer:

Step-by-step explanation:

if im wrong forgive me if im right please mark brainleast

8 0

2 years ago

A rectangular field is 4 times as long as it is wide. If the length is decreased by 10 in. and the width is increased by 2in. th

Keith_Richards [23]

I think the original width was 9.6 in and the original length was 38.4 in.
Hope this will help u

5 0

2 years ago